2013 tennis event results
Victoria Azarenka was the defending champion, but chose not to participate this year.
Agnieszka Radwańska won the title, defeating Dominika Cibulková in the final, 6–0, 6–0. This was only the eighth WTA singles final to be won with a 6–0, 6–0 (a "double bagel") scoreline in history, and the first since Marion Bartoli won the 2006 Challenge Bell.
Top half[edit]
Bottom half[edit]
Qualifying[edit]
Qualifiers[edit]
First qualifier[edit]
Second qualifier[edit]
Third qualifier[edit]
Fourth qualifier[edit]
Fifth qualifier[edit]
Sixth qualifier[edit]
External links[edit]
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Grand Slam events | |
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WTA Premier Mandatory tournaments | |
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WTA Premier 5 tournaments | |
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WTA Premier tournaments | - Brisbane (S, D)
- Sydney (S, D)
- Paris (S, D)
- Dubai (S, D)
- Charleston (S, D)
- Stuttgart (S, D)
- Brussels (S, D)
- Eastbourne (S, D)
- Stanford (S, D)
- Carlsbad (S, D)
- New Haven (S, D)
- Moscow (S, D)
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WTA International tournaments | - Auckland (S, D)
- Shenzhen (S, D)
- Hobart (S, D)
- Pattaya City (S, D)
- Bogotá (S, D)
- Memphis (S, D)
- Acapulco (S, D)
- Kuala Lumpur (S, D)
- Florianópolis (S, D)
- Monterrey (S, D)
- Katowice (S, D)
- Fes (S, D)
- Estoril (S, D)
- Strasbourg (S, D)
- Birmingham (S, D)
- Nuremberg (S, D)
- 's-Hertogenbosch (S, D)
- Budapest (S, D)
- Palermo (S, D)
- Båstad (S, D)
- Bad Gastein (S, D)
- Baku (S, D)
- Washington D.C. (S, D)
- Tashkent (S, D)
- Quebec City (S, D)
- Seoul (S, D)
- Guangzhou (S, D)
- Linz (S, D)
- Osaka (S, D)
- Luxembourg City (S, D)
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Team events | |
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